这个比较繁琐，谁有更好方法？告诉我
[root@module tmp]# cat oldboy.txt
12s
120001ms
12000000us
13s
[root@module tmp]# grep ‘[0-9]\+s‘ oldboy.txt |sed ‘s#s#000000#g‘>oldboy1.txt
[root@module tmp]# cat oldboy1.txt
12000000
13000000
[root@module tmp]# grep ‘[0-9]\+us‘ oldboy.txt |sed ‘s#us##g‘>>oldboy1.txt
[root@module tmp]# cat oldboy1.txt
12000000
13000000
12000000
[root@module tmp]# grep ‘[0-9]\+ms‘ oldboy.txt |sed ‘s#ms#000#g‘>>oldboy1.txt
[root@module tmp]# cat oldboy1.txt
12000000
13000000
12000000
120001000
[root@module tmp]# cat oldboy1.txt |sort -n
12000000
12000000
13000000
120001000
日志时间格式有s,ms,us,如何排序最大10行
原文：http://www.cnblogs.com/changyaoguo/p/5959788.html
