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270. Closest Binary Search Tree Value

时间:2016-10-13 07:44:09      阅读:173      评论:0      收藏:0      [点我收藏+]

Given a non-empty binary search tree and a target value, find the value in the BST that is closest to the target.

Note:

  • Given target value is a floating point.
  • You are guaranteed to have only one unique value in the BST that is closest to the target.
/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
    public int closestValue(TreeNode root, double target) {
        if(root == null) return 0;
        int ret = root.val;
        while(root != null){
            if(Math.abs(ret - target) > Math.abs(root.val - target)){
                ret = root.val;
            }
            root = root.val > target ? root.left : root.right;
        }
        return ret;
    }

}

 

270. Closest Binary Search Tree Value

原文:http://www.cnblogs.com/joannacode/p/5955046.html

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