java判断乱码

开发需要，判断乱码，baidu了一下，基本都是同一份代码

if (!Character.isLetterOrDigit(c)) {        ->  这个有问题，中文文字被识别成字母及数字

改用：if(!(CharUtils.isAsciiAlpha(c) || CharUtils.isAsciiNumeric(c))){     -> 要apache的lang包

Mark一下：

char c=...;

Character.UnicodeBlock ub = Character.UnicodeBlock.of(c);
if (ub == Character.UnicodeBlock.CJK_UNIFIED_IDEOGRAPHS
|| ub == Character.UnicodeBlock.CJK_UNIFIED_IDEOGRAPHS_EXTENSION_A
|| ub == Character.UnicodeBlock.CJK_UNIFIED_IDEOGRAPHS_EXTENSION_B
|| ub == Character.UnicodeBlock.CJK_UNIFIED_IDEOGRAPHS_EXTENSION_C
|| ub == Character.UnicodeBlock.CJK_UNIFIED_IDEOGRAPHS_EXTENSION_D
|| ub == Character.UnicodeBlock.CJK_COMPATIBILITY_FORMS
|| ub == Character.UnicodeBlock.CJK_COMPATIBILITY_IDEOGRAPHS
|| ub == Character.UnicodeBlock.CJK_COMPATIBILITY_IDEOGRAPHS_SUPPLEMENT
|| ub == Character.UnicodeBlock.CJK_SYMBOLS_AND_PUNCTUATION
|| ub == Character.UnicodeBlock.GENERAL_PUNCTUATION
|| ub == Character.UnicodeBlock.HALFWIDTH_AND_FULLWIDTH_FORMS
|| ub == Character.UnicodeBlock.VERTICAL_FORMS

常量说明：http://lwjlaser.iteye.com/blog/963211

java判断乱码

原文：http://www.cnblogs.com/abinxm/p/5889065.html