| Time Limit: 1000MS | Memory Limit: 30000K | |
| Total Submissions: 23332 | Accepted: 11779 |
Description
Input
Output
Sample Input
2 16 3 27 7 4357186184021382204544
Sample Output
4 3 1234
Source
#include <cstdio>
#include <cmath>
int main()
{
double n, p;
while(~scanf("%lf%lf", &n, &p)){
printf("%.0f\n", pow(p, 1/n));
}
return 0;
}
POJ 2109 Power of Cryptography
原文:http://www.cnblogs.com/inmoonlight/p/5837887.html