首页 > 其他 > 详细

[LeetCode] NO. 100 Same Tree

时间:2016-08-17 00:00:17      阅读:293      评论:0      收藏:0      [点我收藏+]

[题目] 

Given two binary trees, write a function to check if they are equal or not.

Two binary trees are considered equal if they are structurally identical and the nodes have the same value.

 

[题目解析]  二叉树的问题,转化成当前节点与左子树,右子树问题。注意一些临界条件的判断。

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
    public boolean isSameTree(TreeNode p, TreeNode q) {
        if(null == p && null == q) return true;
        if(null != p && null != q){
            return (p.val == q.val && isSameTree(p.left,q.left) && isSameTree(p.right,q.right));
        }else{
            return false;
        }
    }
}

 

[LeetCode] NO. 100 Same Tree

原文:http://www.cnblogs.com/zzchit/p/5778166.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!