题目链接:
Time Limit: 8000/4000 MS (Java/Others)
Memory Limit: 65536/65536 K (Java/Others)
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <bits/stdc++.h>
#include <stack>
#include <map>
using namespace std;
#define For(i,j,n) for(int i=j;i<=n;i++)
#define mst(ss,b) memset(ss,b,sizeof(ss));
typedef long long LL;
template<class T> void read(T&num) {
char CH; bool F=false;
for(CH=getchar();CH<‘0‘||CH>‘9‘;F= CH==‘-‘,CH=getchar());
for(num=0;CH>=‘0‘&&CH<=‘9‘;num=num*10+CH-‘0‘,CH=getchar());
F && (num=-num);
}
int stk[70], tp;
template<class T> inline void print(T p) {
if(!p) { puts("0"); return; }
while(p) stk[++ tp] = p%10, p/=10;
while(tp) putchar(stk[tp--] + ‘0‘);
putchar(‘\n‘);
}
const LL mod=1e9+7;
const double PI=acos(-1.0);
const int inf=1e18;
const int N=1e5+10;
const int maxn=5e3+4;
const double eps=1e-12;
stack<int>a,b,c,d;
char s[10],st[10],str[10];
LL temp[N];
int main()
{
int Case=0;
LL x;
while(1)
{
int n,cnt=0;
read(n);
if(n==0)break;
while(!a.empty())a.pop();
while(!b.empty())b.pop();
while(!c.empty())c.pop();
printf("Case #%d:\n",++Case);
For(i,1,n)
{
scanf("%s%s",s,str);
if(s[0]==‘p‘)
{
if(s[1]==‘u‘)
{
scanf("%lld",&x);
temp[++cnt]=x;
if(str[0]==‘A‘)a.push(cnt);
else b.push(cnt);
}
else
{
if(str[0]==‘A‘&&!a.empty())
{
printf("%lld\n",temp[a.top()]);
a.pop();
}
else if(str[0]==‘B‘&&!b.empty())
{
printf("%lld\n",temp[b.top()]);
b.pop();
}
else
{
printf("%lld\n",temp[c.top()]);
c.pop();
}
}
}
else
{
scanf("%s",st);
while(!a.empty()||!b.empty())
{
int A,B;
if(a.empty())A=0;
else A=a.top();
if(b.empty())B=0;
else B=b.top();
if(A>B)
{
a.pop();
d.push(A);
}
else
{
b.pop();
d.push(B);
}
}
while(!d.empty())
{
c.push(d.top());
d.pop();
}
}
}
}
return 0;
}
原文:http://www.cnblogs.com/zhangchengc919/p/5755076.html