首页 > 其他 > 详细

leetcode No70. Climbing Stairs

时间:2016-08-04 13:33:53      阅读:347      评论:0      收藏:0      [点我收藏+]

Question:

You are climbing a stair case. It takes n steps to reach to the top.

Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?

爬楼梯,一次只能爬1阶或者2阶,问总共有多少种结果。

Algorithm:

Dynamic Programming动态规划,s[i]=s[i-1]+s[i-2]

Accepted Code:

class Solution {
public:
    int climbStairs(int n) {
        if(n==0)return 0;
        else if(n==1)return 1;
        else if(n==2)return 2;
        vector<int> res(n,0);
        res[0]=1;
        res[1]=2;
        for(int i=2;i<n;i++)
            res[i]=res[i-1]+res[i-2];
        return res[n-1];
    }
};



leetcode No70. Climbing Stairs

原文:http://blog.csdn.net/u011391629/article/details/52116336

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!