Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
class Solution {
public:
int minPathSum(vector<vector<int>>& grid) {
int M=grid.size();
int N=grid[0].size();
if(M==0) return 0;
vector<vector<int>> res(grid);
for(int j=1;j<N;j++) //先要把边界的算出来
res[0][j]+=res[0][j-1];
for(int i=1;i<M;i++)
res[i][0]+=res[i-1][0];
for(int i=1;i<M;i++)
for(int j=1;j<N;j++)
{
res[i][j]=min(res[i-1][j],res[i][j-1])+res[i][j];
}
return res[M-1][N-1];
}
};leetcode No64. Minimum Path Sum
原文:http://blog.csdn.net/u011391629/article/details/52097867