Description
Input
Output
Sample Input
5 6
1 2 3 4 5 Q 1 5 U 3 6 Q 3 4 Q 4 5 U 2 9 Q 1 5
Sample Output
5 6 5 9
代码如下:
#include "stdio.h" #include <cstdio> #include <climits> using namespace std; #define M ((L+R)>>1) #define lson rt<<1,L,M #define rson rt<<1|1,M+1,R #define root 1,1,N #define max(a,b) ((a>b)?a:b) const int maxn = 200001; int maxv[maxn << 2],ql,qr,tar,v,val[maxn]; inline void pushup(int rt) { maxv[rt] = max(maxv[rt<<1],maxv[rt<<1|1]); } void build(int rt,int L,int R) { if(L == R) maxv[rt] = val[L]; else { build(lson); build(rson); pushup(rt); } } void update(int rt,int L,int R) { if(L == R) maxv[rt] = v; else { if(tar <= M) update(lson); if(tar > M) update(rson); pushup(rt); } } int query(int rt,int L,int R) { if(ql <= L && qr >= R) return maxv[rt]; int lv = -INT_MAX,rv = -INT_MAX; if(ql <= M) lv = query(lson); if(qr > M) rv = query(rson); return max(lv,rv); } int main() { int N,m; char cmd; while(~scanf("%d%d",&N,&m)) { for(int i = 1;i <= N;i++) scanf("%d",val + i); build(root); for(int i = 1;i <= m;i++) { scanf(" %c",&cmd); if(cmd == ‘Q‘) { scanf("%d%d",&ql,&qr); printf("%d\n",query(root)); } else { scanf("%d%d",&tar,&v); update(root); } } } return 0; }
原文:http://www.cnblogs.com/llfj/p/5701506.html