题目链接:
Time Limit: 4000/2000 MS (Java/Others)
Memory Limit: 131072/131072 K (Java/Others)
#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <cmath>
//#include <bits/stdc++.h>
#include <stack>
using namespace std;
#define For(i,j,n) for(int i=j;i<=n;i++)
#define mst(ss,b) memset(ss,b,sizeof(ss));
typedef long long LL;
template<class T> void read(T&num) {
char CH; bool F=false;
for(CH=getchar();CH<‘0‘||CH>‘9‘;F= CH==‘-‘,CH=getchar());
for(num=0;CH>=‘0‘&&CH<=‘9‘;num=num*10+CH-‘0‘,CH=getchar());
F && (num=-num);
}
int stk[70], tp;
template<class T> inline void print(T p) {
if(!p) { puts("0"); return; }
while(p) stk[++ tp] = p%10, p/=10;
while(tp) putchar(stk[tp--] + ‘0‘);
putchar(‘\n‘);
}
const LL mod=1e9+7;
const double PI=acos(-1.0);
const int inf=1e9;
const int N=1e5+10;
const int maxn=500+10;
const double eps=1e-8;
LL f[60];
void Init()
{
f[0]=1;
For(i,1,50)
{
f[i]=f[i-1]*2;
}
}
int main()
{
int t;
read(t);
Init();
while(t--)
{
int n,m;
read(n);read(m);
int ans=0;
for(int i=min(40,m);i>=0;i--)
{
if(n>=f[i])
{
ans+=n/f[i];
n=n%f[i];
}
}
printf("%d\n",ans);
}
return 0;
}
原文:http://www.cnblogs.com/zhangchengc919/p/5699881.html