字符串操作
${#string}输出字句的字符个数
${string:position:length}输出$position开始的length长度的字符
${string:position}
[root@ilove scripts]# liuyifei="i like sanpan i like luo swimming"
[root@ilove scripts]# echo ${#liuyifei}
33
[root@ilove scripts]# echo ${liuyifei:2:4}
like
[root@ilove scripts]# echo ${liuyifei:2}
like sanpan i like luo swimming
====以上实测
${string#substring}从string中从前往后检索，只要匹配到字符就开始删除最短匹配
${string##substring}从头匹配，开始最长删除
${string%substring}从结尾开始
${string%%substring}从结尾开始，类似以上##
======以上必须必须从一开始就匹配上
[root@ilove scripts]# echo ${liuyifei#like}
i like sanpan i like luo swimming
[root@ilove scripts]# echo ${liuyifei#*like}
sanpan i like luo swimming
[root@ilove scripts]# echo ${liuyifei##*like}
luo swimming
[root@ilove scripts]# echo ${liuyifei%*like}
i like sanpan i like luo swimming
[root@ilove scripts]# echo ${liuyifei%like}
i like sanpan i like luo swimming
[root@ilove scripts]# echo ${liuyifei%like*}
i like sanpan i
[root@ilove scripts]# echo ${liuyifei%%like*}
i========================
${string/substring/replace}替换第一个遇到的匹配的字符
${string/#substring/replace}前缀匹配，必须全部匹配上，替换一长条
${string/%substring/replace}从后往前，替换最后一个遇到的匹配字符，必须全部匹配
[root@ilove scripts]# echo ${liuyifei/like/love}
i love sanpan i like luo swimming
[root@ilove scripts]# echo ${liuyifei/#*like/love}
love luo swimming
[root@ilove scripts]# echo ${liuyifei/%like*/love}
i love
个人总结：在shell变量操作中 出现# % 就必须一直予以匹配才能进行相关操作
原文：http://singler.blog.51cto.com/3984787/1812414