Given a collection of intervals, merge all overlapping intervals.
For example,
Given [1,3],[2,6],[8,10],[15,18],
return [1,6],[8,10],[15,18].
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问题很简单,直接看代码。
java code:
/**
* Definition for an interval.
* public class Interval {
* int start;
* int end;
* Interval() { start = 0; end = 0; }
* Interval(int s, int e) { start = s; end = e; }
* }
*/
public class Solution {
public List<Interval> merge(List<Interval> intervals) {
List<Interval> result = new ArrayList<>();
if(intervals == null || intervals.size() == 0) return result;
Collections.sort(intervals, new Comparator<Interval>(){
@Override
public int compare(Interval val1, Interval val2) {
return Integer.compare(val1.start, val2.start);
}
});
int start = intervals.get(0).start;
int end = intervals.get(0).end;
for(Interval val: intervals) {
if(val.start <= end) {
end = Math.max(end, val.end);
}else{
result.add(new Interval(start, end));
start = val.start;
end = val.end;
}
}
result.add(new Interval(start, end));
return result;
}
}原文:http://blog.csdn.net/itismelzp/article/details/51800491