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Intersection of Two Arrays II

时间:2016-06-14 08:50:26      阅读:212      评论:0      收藏:0      [点我收藏+]

Given two arrays, write a function to compute their intersection.

Example:
Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2].

Note:

    • Each element in the result should appear as many times as it shows in both arrays.
    • The result can be in any order.
      • 解题思路:双指针, 排序
         1 public class Solution {
         2     public int[] intersect(int[] nums1, int[] nums2) {
         3         Arrays.sort(nums1);
         4         Arrays.sort(nums2);
         5         int i = 0, j = 0;
         6         int index = 0;
         7         int[] temp = new int[nums1.length];
         8         while (i < nums1.length && j < nums2.length) {
         9             if (nums1[i] == nums2[j]) {
        10                 temp[index++] = nums1[i];
        11                 ++i;
        12                 ++j;
        13             } else if (nums1[i] < nums2[j]) {
        14                 i++;
        15             } else {
        16                 j++;
        17             }
        18         }
        19         int[] result = new int[index];
        20         for (int k = 0; k < index; k++) {
        21             result[k] = temp[k];
        22         }
        23         return result;
        24     }
        25 }

         

Intersection of Two Arrays II

原文:http://www.cnblogs.com/FLAGyuri/p/5582719.html

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