js接受url参数

1.正则表达式
function getQueryString(name) {
var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)", "i");
var r = window.location.search.substr(1).match(reg);
if (r != null) return unescape(r[2]); return null;
} 
使用方法：
alert(GetQueryString("参数名1"));alert(GetQueryString("参数名2")); 
alert(GetQueryString("参数名3"));

2.自定义解析
<Script language="javascript">
function GetRequest() {
    var url = location.search; //获取url中"?"符后的字串
    var theRequest = new Object();
    if (url.indexOf("?") != -1) {
        var str = url.substr(1);
        strs = str.split("&");
        for(var i = 0; i < strs.length; i ++) {
            theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]);
        }
    }
    return theRequest;
}
</Script>
使用方法：
<Script language="javascript"> 
var Request = new Object(); 
Request = GetRequest(); 
var 参数1,参数2,参数3,参数N; 
参数1 = Request[‘参数1‘]; 
参数2 = Request[‘参数2‘]; 
参数3 = Request[‘参数3‘]; 
参数N = Request[‘参数N‘]; 
</Script>