【Leetcode】Coin Change

题目链接：https://leetcode.com/problems/coin-change/
题目：

You are given coins of different denominations and a total amount of money amount. Write a function to compute the fewest number of coins that you need to make up that amount. If that amount of money cannot be made up by any combination of the coins, return -1.

Example 1:
coins = [1, 2, 5], amount = 11
return 3 (11 = 5 + 5 + 1)

Example 2:
coins = [2], amount = 3
return -1.

Note:
You may assume that you have an infinite number of each kind of coin.

思路：

c[i]表示数目为i时最少需要多少个硬币。

算法：

public int coinChange(int[] coins, int amount) {  
        int c[] = new int[amount + 1];  
        for (int i = 1; i <= amount; i++) {  
            int min = -1;  
            for (int j = 0; j < coins.length; j++) {  
                if (i - coins[j] >= 0 && c[i - coins[j]] != -1){  
                    if(min==-1){//当第一次判断时   
                        min = c[i-coins[j]]+1;  
                    }else{  
                        min = Math.min(min, c[i - coins[j]] + 1);  
                    }  
                }  
            }  
            c[i] = min;  
        }  
        return c[amount] ;  
    }  

【Leetcode】Coin Change

原文：http://blog.csdn.net/yeqiuzs/article/details/51534198