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【Leetcode】Search a 2D Matrix II

时间:2016-05-27 11:56:15      阅读:126      评论:0      收藏:0      [点我收藏+]

题目链接:https://leetcode.com/problems/search-a-2d-matrix-ii/
题目:

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:

  • Integers in each row are sorted in ascending from left to right.
  • Integers in each column are sorted in ascending from top to bottom.

For example,

Consider the following matrix:

[
  [1,   4,  7, 11, 15],
  [2,   5,  8, 12, 19],
  [3,   6,  9, 16, 22],
  [10, 13, 14, 17, 24],
  [18, 21, 23, 26, 30]
]

Given target = 5, return true.

Given target = 20, return false.

思路:

从左上角开始搜索。因为matrix[i][j]小于所有>i 或>j的元素,也就是讲只有0~i 和0~j的元素无法确定大小。

算法:

public boolean searchMatrix(int[][] matrix, int target) {  
int j = matrix[0].length-1,i=0;   
while(i<matrix.length&&j>=0){  
     if(matrix[i][j]>target){  
         j--;  
     }else if(matrix[i][j]<target){  
         i++;  
     }else{  
         return true;  
     }  
 }  
return false;  
}  


【Leetcode】Search a 2D Matrix II

原文:http://blog.csdn.net/yeqiuzs/article/details/51501280

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