1,0 2,1 4,2,0 1,2,0 1 10,6,4,2,1 0 0
1,0,1 1,1,1,0 1,0,0,0,0,0
细心点 把,分割的数字读取出来就行了
#include <stdio.h>
#include <string.h>
#include <stack>
#include <math.h>
using namespace std;
int main()
{
char num1[1000];
char num2[1000];
int prim[26]={0,2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,83,89,97};
while(~scanf("%s %s",num1,num2))
{
if(strcmp(num1,"0")==0&&strcmp(num2,"0")==0)
break;
int len1=strlen(num1);
int len2=strlen(num2);
int t1=len1-1,t2=len2-1;
stack<int>s;
int r=0;
int cnt=1;
while(t1>=0||t2>=0)
{
int mul=0;
int a=0,b=0;
for(;t1>=0;t1--)
{
if(num1[t1]>='0'&&num1[t1]<='9')
a=a+(num1[t1]-'0')*pow(10,mul++);
else
break;
}
mul=0;
for(;t2>=0;t2--)
{
if(num2[t2]>='0'&&num2[t2]<='9')
b=b+(num2[t2]-'0')*pow(10,mul++);
else
break;
}
// printf("r=%d \n",a+b+r);
s.push((a+b+r)%prim[cnt]);
r=(a+b+r)/prim[cnt];
t1--,t2--,cnt++;
}
if(r)
s.push(r);
printf("%d",s.top());s.pop();
while(!s.empty())
printf(",%d",s.top()),s.pop();
printf("\n");
}
}
原文:http://blog.csdn.net/su20145104009/article/details/51336876