Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times.
You may assume that the array is non-empty and the majority element always exist in the array.
public class Solution { //更好的方法是排序，return 中间那个数
public int majorityElement(int[] nums) {
Map<Integer, Integer> map = new HashMap<Integer, Integer>();
for (int i = 0; i < nums.length; i++) {
if (map.containsKey(nums[i])) {
map.put(nums[i], map.get(nums[i])+1);
} else
map.put(nums[i], 1);
}
Set set = map.entrySet();
Iterator it = set.iterator();
int res = 0;
while (it.hasNext()) {
Map.Entry entry = (Map.Entry) it.next();
if ((int) entry.getValue() > nums.length / 2)
res = (int) entry.getKey();
}
return res;
}
}
原文：http://www.cnblogs.com/kydnn/p/5380766.html