注意是sorted,两个以排序好的。主要区分情况就能做完
class Solution {
public:
    ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) {
              if(l1 == NULL) {
    return l2;
  }
  if(l2 == NULL) {
    return l1;
  }
            ListNode* p1;
            ListNode* p2;
            if(l1->val > l2->val) {
                p1 = l1;
                p2 = l2;
            }
            else {
                p1 = l2;
                p2 = l1;
            }
            ListNode* head = p2;
            while(p2->next != NULL) {
                //不存在p2是尾结点
                if(p1->val > p2->next->val) {
                    p2 = p2->next;
                    continue;
                }
                else {
                    if(p1->next == NULL) {
                        p1->next = p2->next;
                        p2->next = p1;
                        return head;
                    }
                    ListNode* q = p1;
                    p1 = p1->next;
                    q->next = p2->next;
                    p2->next = q;
                    continue;
                }
            }
            //如果p2是尾结点
            p2->next = p1;
            return head;
        }
};
原文:http://www.cnblogs.com/xdlyy/p/5357184.html