Python代码如下：
def solution(A):
# write your code in Python 2.6
curZeroCnt = 0
totalPairs = 0
for value in A:
if value == 0:
curZeroCnt += 1
else:
totalPairs += curZeroCnt
if totalPairs > 1000000000:
return -1
else:
return totalPairs
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原文：http://blog.csdn.net/sunbaigui/article/details/24273113