mysql 时间差问题集锦

SELECT * from grouptoadd where taskid = ‘103244‘;

select datediff(max(spreadtime),min(createtime)) from grouptoadd where taskid = ‘103244‘;

-- 【mysql】时间差
SELECT TIMESTAMPDIFF(DAY, createtime ,spreadtime) AS `DAY` from grouptoadd where taskid = ‘103244‘;

SELECT TIMESTAMPDIFF(HOUR, createtime ,spreadtime) AS `HOUR` from grouptoadd where taskid = ‘103244‘;

SELECT TIMESTAMPDIFF(MINUTE, createtime ,spreadtime) AS `MINUTE` from grouptoadd where taskid = ‘103244‘;

SELECT TIMESTAMPDIFF(SECOND, createtime ,spreadtime) AS `Second` from grouptoadd where taskid = ‘103244‘;

mysql 时间差问题集锦

原文：http://www.cnblogs.com/wvqusrtg/p/5201729.html