Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 13382 Accepted Submission(s): 8538
#include<cstdio> #include<cstring> using namespace std; char a[1005]; char b[1005]; int lena,lenb; int next[1005]; void getnext() { int i=0,k=-1; next[0]=-1; while(i<lenb) { if(k==-1||b[i]==b[k]) { i++; k++; next[i]=k; } else k=next[k]; } } int KMP() { getnext(); int i=0,j=0; int cnt=0; while(i<lena) { if(j==-1||a[i]==b[j]) { i++; j++; } else j=next[j]; if(j==lenb) { cnt++; j=0;//若两个不同的匹配没有交集则j=0,若存在交集则j=next[j]; } } return cnt; } int main() { while(scanf("%s",a)!=EOF) { if(*a==‘#‘) break; scanf("%s",b); lena=strlen(a); lenb=strlen(b); printf("%d\n",KMP()); } return 0; }
原文:http://www.cnblogs.com/program-ccc/p/5198913.html