首页 > Web开发 > 详细

Shell脚本实现的猜数字小游戏

时间:2016-02-05 17:16:47      阅读:251      评论:0      收藏:0      [点我收藏+]

生成的密码和用户输入可以接受重复数字。
所以相对一般规则的猜数字可能难度要大不少。

本版本规则:

A--数字对,位置也对
B--排除A的结果后,数字对,但位置不对

开始后,系统化初始化一个4位可重复数字,如“1223”。假设用户第一次输入“1234”,那么系统将提示“2A1B”,前两位数字“12”相同并且位置也相同,为“2A”。后两位数字中,用户输入的“3”与密文中“3”相同,但两者位置不同,则为“1B”,最终结果为“2A1B”。

再假设用户此时输入“1232”,那么结果则为“2A2B”,计算方法与前次一样。

代码如下:

复制代码 代码如下:

#!/bin/bash
clear
echo
echo "###################################################################"
echo "#  this is a bash-shell game write by Email:breeze7086@gmail.com  #"
echo "# the game called *digits*,and this version have repeated numbers #"
echo "#                           version 1.0                           #"
echo "###################################################################"
echo -e "\n\n"
declare INPUT
declare PASSWORD
declare A
declare B
declare X
declare Y
declare LOOP
#This funtion init the variable PASSWORD that user need to guess
init_password()
{
        PASSWORD=`echo $(($RANDOM%10000))`
        echo $PASSWORD | grep ‘^[0-9]\{4\}$‘ >/dev/null 2>&1
        if [ $? != 0 ]
        then
                init_password
        else
                input
        fi
}
#This funtion accept the input from user‘s keyboard
input()
{
        echo -n "please input a number between 0000-9999:"
        read INPUT
        echo $INPUT | grep ‘^[0-9]\{4\}$‘ >/dev/null 2>&1
        if [ $? != 0 ]
        then
                echo "retry a number between 0000-9999 and do not input a char"
                input
        else
                judge
        fi
}
#This funtion is the main funtion
judge()
{
        X=$INPUT
        Y=$PASSWORD
        while [ $INPUT != $PASSWORD ]
        do
                A=0
                B=0
                judge_a
                judge_b
                LOOP=`expr $LOOP + 1`
                echo "****************************"
                echo "*           "$A"A"$B"B           *"
                echo "****************************"
                input
        done
}
#This funtion count the variable A‘s value
judge_a()
{
                for i in `seq 4`
                do
                        VAR_INPUT=`expr substr "$X" $i 1`
                        for j in `seq 4`
                        do
                                VAR_PASSWORD=`expr substr "$Y" $j 1`
                                if [[ $VAR_INPUT = $VAR_PASSWORD && $VAR_INPUT != "" && $VAR_PASSWORD != "" && $i = $j ]]
                                then
                                        A=`expr $A + 1`
                                        X=`expr substr $X 1 "$[$i-1]"``expr substr $X "$[$i+1]" 4`
                                        Y=`expr substr $Y 1 "$[$i-1]"``expr substr $Y "$[$i+1]" 4`
                                        judge_a
                                fi
                        done
                done
}
#This funtion count the variable B‘s value
judge_b()
{
                for i in `seq 4`
                do
                        VAR_INPUT=`expr substr "$X" $i 1`
                        for j in `seq 4`
                        do
                                VAR_PASSWORD=`expr substr "$Y" $j 1`
                                if [[ $VAR_INPUT = $VAR_PASSWORD && $VAR_INPUT != "" && $VAR_PASSWORD != "" ]]
                                then
                                        B=`expr $B + 1`
                                        X=`expr substr "$X" 1 "$[$i-1]"``expr substr "$X" "$[$i+1]" 4`
                                        Y=`expr substr "$Y" 1 "$[$j-1]"``expr substr "$Y" "$[$j+1]" 4`
                                        judge_b
                                fi
                        done
                done
}
#This is the begin of script
LOOP=1
init_password
echo "#############################################"
echo "#congratulations!You have tried $LOOP times!    #"
echo "#        The password is $PASSWORD !             #"
echo "#############################################"

Shell脚本实现的猜数字小游戏

原文:http://www.jb51.net/article/58859.htm

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!