LeetCode 137. Single Number II

再来一道，刷简单题。

?

137. Single Number II

?

Given an array of integers, every element appears?three?times except for one. Find that single one.

Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?

?

题目思路和136一致，只需要将步长设为3即可，分析过程见我blog

public class Solution {
    public int singleNumber(int[] nums) {
        Arrays.sort(nums);
        
        int index = 0;
        while(index < nums.length - 2) {
            if (nums[index] - nums[index + 1] == 0 && nums[index] - nums[index + 2] == 0) {
                index += 3;
            } else {
                return nums[index];
            }
        }
        return nums[index];
    }
}

?

?

LeetCode 137. Single Number II

原文：http://leonard1853.iteye.com/blog/2275633