测试代码如下：
class ModelMetaClass(type):
def __new__(cls,name,base,attrs):
logging.info("cls is:"+str(cls))
logging.info("name is:"+str(name))
logging.info("base is:"+str(base))
logging.info("attrs is:"+str(attrs))
return type.__new__(cls,name,base,attrs)
pass
pass
class Model(dict):
__metaclass__ = ModelMetaClass
def __init__(self):
pass
pass
def main():
m=Model()
if __name__ == ‘__main__‘:
main()
测试结果：
INFO:root:cls is:<class ‘__main__.ModelMetaClass‘>
INFO:root:name is:Model
INFO:root:base is:(<type ‘dict‘>,)
INFO:root:attrs is:{‘__module__‘: ‘__main__‘, ‘__metaclass__‘: <class ‘__main__.ModelMetaClass‘>, ‘__init__‘: <function __init__ at 0x025C76F0>}
结论就显而易见了。cls是当前类的名字，即类本身。name是通过__metaclass__属性指向ModelMetaClass的类，即要实例化的类，ModelMetaClass拦截了该类的实例化。base是要实例化的类的基类。attrs是要实例化的类的属性集合。Python中type的构造函数参数含义说明
原文：http://www.jb51.net/article/68222.htm
