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【Leetcode】Scramble String

时间:2014-04-15 01:16:18      阅读:485      评论:0      收藏:0      [点我收藏+]

Given a string s1, we may represent it as a binary tree by partitioning it to two non-empty substrings recursively.

Below is one possible representation of s1 = "great":

    great
   /      gr    eat
 / \    /  g   r  e   at
           /           a   t

To scramble the string, we may choose any non-leaf node and swap its two children.

For example, if we choose the node "gr" and swap its two children, it produces a scrambled string "rgeat".

    rgeat
   /      rg    eat
 / \    /  r   g  e   at
           /           a   t

We say that "rgeat" is a scrambled string of "great".

Similarly, if we continue to swap the children of nodes "eat" and "at", it produces a scrambled string "rgtae".

    rgtae
   /      rg    tae
 / \    /  r   g  ta  e
       /       t   a

We say that "rgtae" is a scrambled string of "great".

Given two strings s1 and s2 of the same length, determine if s2 is a scrambled string of s1.

思路:使用递归的方法,判断s1和s2的子串是否分别可以进行重组,如果都可以,则返回true。否则,返回false。

代码:

class Solution {
public:
    bool isScramble(string s1, string s2) {
        string s1_temp = s1, s2_temp = s2;
        if(s1==s2)
            return true;
        if(s1.length()!=s2.length())
            return false;
        sort(s1_temp.begin(),s1_temp.end());
        sort(s2_temp.begin(),s2_temp.end());
        if(s1_temp!=s2_temp)
            return false;
        int size = s1.length();
        for(int i=1;i<size;i++)
        {
            string s1left = s1.substr(0,i);
            string s2left = s2.substr(0,i);
            string s1right = s1.substr(i);
            string s2right = s2.substr(i);
            if(isScramble(s1left,s2left)&&isScramble(s1right,s2right))
                return true;
            s2left = s2.substr(0, size-i);
            s2right = s2.substr(size-i);
            if(isScramble(s1left,s2right)&&isScramble(s1right,s2left))
                return true;
        }
        return false;
    }
};


【Leetcode】Scramble String,布布扣,bubuko.com

【Leetcode】Scramble String

原文:http://blog.csdn.net/hjiam2/article/details/23690077

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