Find the kth largest element in an unsorted array. Note that it is the kth largest element in the sorted order, not the kth distinct element.
For example,
Given [3,2,1,5,6,4]
and k = 2, return 5.
Note:
You may assume k is always valid, 1 ≤ k ≤ array‘s length.
public class Solution { public int findKthLargest(int[] nums, int k) { if (k < 1 || nums == null) { return 0; } return getKth(nums.length - k +1, nums, 0, nums.length - 1); } public int getKth(int k, int[] nums, int start, int end) { int pivot = nums[end];//如果改成start就不对。如何ramdon pivot // System.out.println(pivot); int left = start; int right = end; while (true) { while (nums[left] < pivot && left < right) { left++; } while (nums[right] >= pivot && right > left) { right--; } if (left == right) { break; } swap(nums, left, right); } swap(nums, left, end); //?? if (k == left + 1) { return pivot; } else if (k < left + 1) { return getKth(k, nums, start, left - 1); } else { return getKth(k, nums, left + 1, end); } } public void swap(int[] nums, int n1, int n2) { int tmp = nums[n1]; nums[n1] = nums[n2]; nums[n2] = tmp; } }
quick select, if random pivot?
*Kth Largest Element in an Array
原文:http://www.cnblogs.com/hygeia/p/5129054.html