Given an integer array, find a continuous subarray where the sum of numbers is the biggest. Your code should return the index of the first number and the index of the last number. (If their are duplicate answer, return anyone)
Give [-3, 1, 3, -3, 4]
, return [1,4]
.
public class Solution { /** * @param A an integer array * @return A list of integers includes the index of the first number and the index of the last number */ public ArrayList<Integer> continuousSubarraySum(int[] A) { // Write your code here ArrayList<Integer> list=new ArrayList<Integer>(); if(A.length==0 || A==null) return list; int n=A.length; int curleft=0; int curSum=0; int maxSum=Integer.MIN_VALUE; int maxleft=0; int maxright=0; for(int i=0;i<n;i++) { curSum=curSum+A[i]; if(curSum>maxSum) { maxSum=curSum; maxleft=curleft; maxright=i; } if(curSum<0) { if(i+1<n-1) { curSum=0; curleft=i+1; } } } list.add(maxleft); list.add(maxright); return list; } }
[lintcode medium]Continuous Subarray Sum
原文:http://www.cnblogs.com/kittyamin/p/5111855.html