LeetCode 7 Reverse Integer（反转数字）

 1 public class Solution {
 2     public int reverse(int x) {
 3         long reverse = 0;
 4         
 5         while(x != 0){
 6             reverse = reverse * 10 + x % 10;
 7             if(reverse > Integer.MAX_VALUE || reverse < Integer.MIN_VALUE)
 8                 return 0;
 9             x = x / 10;
10         }
11         return (int)reverse;
12     }
13 }