首页 > 其他 > 详细

[Leetcode] Distinct Subsequences

时间:2014-04-12 14:32:32      阅读:327      评论:0      收藏:0      [点我收藏+]

Given a list, rotate the list to the right by k places, where k is non-negative.

For example:
Given 1->2->3->4->5->NULL and k = 2,
return 4->5->1->2->3->NULL.

K可能会大于链表的长度,坑爹!

bubuko.com,布布扣
 1 /**
 2  * Definition for singly-linked list.
 3  * struct ListNode {
 4  *     int val;
 5  *     ListNode *next;
 6  *     ListNode(int x) : val(x), next(NULL) {}
 7  * };
 8  */
 9 class Solution {
10 public:
11     ListNode *rotateRight(ListNode *head, int k) {
12         if (head == NULL) return NULL;
13         ListNode *tail = head, *kth = head;
14         int n = 0;
15         while (tail != NULL) {
16             ++n;
17             tail = tail->next;
18         }
19         tail = head;
20         k %= n;
21         for (int i = 0; i < k; ++i) {
22             tail = tail->next;
23         }
24         while (tail != NULL && tail->next != NULL) {
25             tail = tail->next;
26             kth = kth->next;
27         }
28         if (tail != NULL) {
29             tail->next = head;
30             head = kth->next;
31             kth->next = NULL;
32         }
33         return head;
34     }
35 };
bubuko.com,布布扣

 

[Leetcode] Distinct Subsequences,布布扣,bubuko.com

[Leetcode] Distinct Subsequences

原文:http://www.cnblogs.com/easonliu/p/3659174.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!