首页 > 其他 > 详细

Leetcode: Isomorphic Strings

时间:2015-12-15 11:57:03      阅读:69      评论:0      收藏:0      [点我收藏+]
Given two strings s and t, determine if they are isomorphic.

Two strings are isomorphic if the characters in s can be replaced to get t.

All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.

For example,
Given "egg", "add", return true.

Given "foo", "bar", return false.

Given "paper", "title", return true.

Note:
You may assume both s and t have the same length.

Use HashMap, but HashMap does not guarantee values() set to be unique. Here we require no two characters may map to the same character. So we should also check if map.values() have duplicates. If yes, return false.

 1 public class Solution {
 2     public boolean isIsomorphic(String s, String t) {
 3         if (s==null || t==null || s.length() != t.length()) return false;
 4         HashMap<Character, Character> map = new HashMap<Character, Character>();
 5         for (int i=0; i<s.length(); i++) {
 6             if (!map.containsKey(s.charAt(i))) {
 7                 if (!(map.values().contains(t.charAt(i)))) {
 8                     map.put(s.charAt(i), t.charAt(i));
 9                 }
10                 else return false;
11             }
12             else if (map.get(s.charAt(i)) != t.charAt(i)) return false;
13         }
14         return true;
15     }
16 }

 

Leetcode: Isomorphic Strings

原文:http://www.cnblogs.com/EdwardLiu/p/5047711.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!