Given a non-negative integer N, your task is to compute the sum of all the digits of N, and output every digit of the sum in English.
Input Specification:
Each input file contains one test case. Each case occupies one line which contains an N (<= 10100).
Output Specification:
For each test case, output in one line the digits of the sum in English words. There must be one space between two consecutive words, but no extra space at the end of a line.
Sample Input:12345Sample Output:
one five
解析：此题需要注意一点，虽然题干上说的是输入integer n，但是input上面说了范围为N (<= 10100).所以我们需要用字符串读取。不能使用int
Code:
/************************************************************************* > File Name: 1005.cpp > Author: > Mail: > Created Time: 2015年12月08日 星期二 19时43分08秒 ************************************************************************/ #include<iostream> #include<sstream> #include<string> using namespace std; string dic[10] = {"zero","one","two","three","four","five","six","seven","eight","nine"}; int main(){ string n; cin>>n; int sum = 0; for(int i=0; i<n.size(); i++){ sum += n[i]-‘0‘; } stringstream ss; ss << sum; string output; ss >> output; for(int i=0; i<output.size(); i++){ cout<<dic[output[i]-‘0‘]; if(i != output.size()-1){ cout<<" "; } } return 0; }
原文：http://www.cnblogs.com/RookieCoder/p/5030767.html