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LeetCode | Container With Most Water

时间:2014-04-10 15:57:40      阅读:435      评论:0      收藏:0      [点我收藏+]

题目

Given n non-negative integers a1a2, ..., an, where each represents a point at coordinate (iai). n vertical lines are drawn such that the two endpoints of line i is at (iai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.

Note: You may not slant the container.

分析

双指针从两头往中间压缩,证明见http://oj.leetcode.com/discuss/1074/anyone-who-has-a-o-n-algorithm中的best answer。

代码

public class ContainerWithMostWater {
	public int maxArea(int[] height) {
		if (height == null || height.length == 0) {
			return 0;
		}
		int max = 0;
		int low = 0;
		int high = height.length - 1;
		while (low < high) {
			if (height[low] < height[high]) {
				max = Math.max(max, (high - low) * height[low]);
				++low;
			} else {
				max = Math.max(max, (high - low) * height[high]);
				--high;
			}
		}
		return max;
	}
}

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LeetCode | Container With Most Water

原文:http://blog.csdn.net/perfect8886/article/details/23334855

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