Time Limit: 5000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 17879 Accepted Submission(s):
6234
1 #include <iostream> 2 #include <cstdio> 3 #include <cstring> 4 #include <algorithm> 5 using namespace std; 6 int max(int a,int b) 7 { 8 return a>b?a:b; 9 } 10 int main() 11 { 12 int i,j,n,m; 13 int a[1005],dp[1005]; 14 while(~scanf("%d",&n)&&n) 15 { 16 for(i=0; i<n; i++) 17 scanf("%d",&a[i]); 18 scanf("%d",&m); 19 sort(a,a+n); //排序,找到最贵的菜 20 if(m<5) //假如饭卡初始金额不足5元,则无法购买任何物品 21 { 22 printf("%d\n",m); 23 continue; 24 } 25 memset(dp,0,sizeof(dp)); 26 for(i=0; i<n-1; i++) //m-5块钱在n-1个物品内最多买多少钱的菜 27 for(j=m-5; j>=a[i]; j--) 28 dp[j]=max(dp[j],dp[j-a[i]]+a[i]); 29 printf("%d\n",m-dp[m-5]-a[n-1]); //计算最少剩余的钱 30 } 31 return 0; 32 }
原文:http://www.cnblogs.com/pshw/p/5023624.html