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[LeetCode] Populating Next Right Pointers in Each Node

时间:2015-12-01 07:08:00      阅读:250      评论:0      收藏:0      [点我收藏+]
public class Solution {
    public void connect(TreeLinkNode root) {
        if (root == null) {
            return;
        }
        Queue<TreeLinkNode> queue = new LinkedList<TreeLinkNode>();
        queue.offer(root);
        while (!queue.isEmpty()) {
            TreeLinkNode right = null;
            int size = queue.size();
            for (int i = 0; i < size; i++) {
                TreeLinkNode node = queue.poll();
                node.next = right;
                right = node;
                if (node.right != null) {
                    queue.offer(node.right);
                }
                if (node.left != null) {
                    queue.offer(node.left);
                }
            }
        }
    }
}

 

[LeetCode] Populating Next Right Pointers in Each Node

原文:http://www.cnblogs.com/vision-love-programming/p/5008990.html

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