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virtual judge(专题一 简单搜索 E)

时间:2015-11-28 01:01:35      阅读:369      评论:0      收藏:0      [点我收藏+]

Description

Given a positive integer n, write a program to find out a nonzero multiple m of n whose decimal representation contains only the digits 0 and 1. You may assume that n is not greater than 200 and there is a corresponding m containing no more than 100 decimal digits.

Input

The input file may contain multiple test cases. Each line contains a value of n (1 <= n <= 200). A line containing a zero terminates the input.

Output

For each value of n in the input print a line containing the corresponding value of m. The decimal representation of m must not contain more than 100 digits. If there are multiple solutions for a given value of n, any one of them is acceptable.

Sample Input

2
6
19
0

Sample Output

10
100100100100100100
111111111111111111
#include"cstdio" 
using namespace std;
int n;
unsigned long long ans;
bool flag;
void dfs(unsigned long long i,int k)
{
    if(flag)    return;    //找结果之后就直接返回 
    if(i%n==0)
    {
        flag=true;
        ans=i;
        return;
    }
    if(k==19)    return; //答案在19为之内,无符号long long 可以保存结果 
    dfs(i*10+0,k+1);
    dfs(i*10+1,k+1);
}
int main()
{
    while(scanf("%d",&n)!=EOF&&n!=0)
    {
        flag=false;
        dfs(1,0);
        printf("%llu\n",ans);
    }
    return 0;
}

 

virtual judge(专题一 简单搜索 E)

原文:http://www.cnblogs.com/program-ccc/p/5002010.html

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