LeetCode -- Pow(x, n)

public class Solution {
    public double MyPow(double x, int n) {
        if(n <= 2){
    		return Math.Pow(x, n);
    	}
    	
    	if(n % 2 == 0){
    		var y = MyPow(x, n/2) ;
    		return y * y;
    	}
    	else{
    		var y = MyPow(x, (n-1)/2);
    		return x * y * y;
    	}
    }
}

LeetCode -- Pow(x, n)

原文：http://blog.csdn.net/lan_liang/article/details/49188419