首页 > 移动平台 > 详细

POJ 2773 Happy 2006

时间:2015-10-01 11:38:26      阅读:211      评论:0      收藏:0      [点我收藏+]

Happy 2006

Time Limit: 3000ms
Memory Limit: 65536KB
This problem will be judged on PKU. Original ID: 2773
64-bit integer IO format: %lld      Java class name: Main
 
Two positive integers are said to be relatively prime to each other if the Great Common Divisor (GCD) is 1. For instance, 1, 3, 5, 7, 9...are all relatively prime to 2006.

Now your job is easy: for the given integer m, find the K-th element which is relatively prime to m when these elements are sorted in ascending order.
 

Input

The input contains multiple test cases. For each test case, it contains two integers m (1 <= m <= 1000000), K (1 <= K <= 100000000).
 

Output

Output the K-th element in a single line.
 

Sample Input

2006 1
2006 2
2006 3

Sample Output

1
3
5

Source

 
解题:容斥原理
技术分享
 1 #include <iostream>
 2 #include <cstdio>
 3 #include <cstring>
 4 using namespace std;
 5 typedef long long LL;
 6 const LL INF = 0x3f3f3f3f3f3f3f3f;
 7 const int maxn = 50;
 8 int p[maxn],tot;
 9 void init(int x){
10     tot = 0;
11     for(int i = 2; i*i <= x; ++i){
12         if(x%i == 0){
13             p[tot++] = i;
14             while(x%i == 0) x /= i;
15         }
16     }
17     if(x > 1) p[tot++] = x;
18 }
19 LL solve(LL x){
20     LL ret = 0;
21     for(int i = 1; i < (1<<tot); ++i){
22         int cnt = 0,tmp = 1;
23         for(int j = 0; j < tot; ++j){
24             if((i>>j)&1){
25                 ++cnt;
26                 tmp *= p[j];
27             }
28         }
29         if(cnt&1) ret -= x/tmp;
30         else ret += x/tmp;
31     }
32     return x + ret;
33 }
34 int main(){
35     int n,k;
36     while(~scanf("%d%d",&n,&k)){
37         LL ret = 0,low = 1,high = INF;
38         init(n);
39         while(low <= high){
40             LL mid = (low + high)>>1;
41             if(solve(mid) >= k){
42                 ret = mid;
43                 high = mid - 1;
44             }else low = mid + 1;
45         }
46         printf("%I64d\n",ret);
47     }
48     return 0;
49 }
View Code

 

POJ 2773 Happy 2006

原文:http://www.cnblogs.com/crackpotisback/p/4850806.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!