Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 40200 Accepted Submission(s):
15181
1 #include <iostream> 2 using namespace std; 3 __int64 a[5]; 4 void xx(int t) //通过打表找规律,发现N^N的个位数字4个一循环,而且只需要保存个位数 5 { 6 __int64 i,s=1; 7 t%=10; 8 for(i=1; i<=4; i++) 9 { 10 s*=t; 11 a[i]=s%10; 12 } 13 } 14 int main() 15 { 16 int n,s,t; 17 cin>>n; 18 while(n--) 19 { 20 cin>>t; 21 xx(t); 22 s=t%4; 23 if(s==0) 24 cout<<a[4]<<endl; 25 else 26 cout<<a[s]<<endl; 27 } 28 return 0; 29 }
原文:http://www.cnblogs.com/pshw/p/4815534.html