3
1
100
1
1 1
5
1 2 3 4 5
5
1 2
1 3
2 4
3 4
3 5
3
1 999999 1
4
1 1
1 2
2 3
3 3
区间最大值 线段树
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <iostream>
#include <algorithm>
using namespace std;
const int oo = 0x3f3f3f3f;
const int N = 1005;
typedef long long LL;
struct da
{
int left, right, val;
}as[N*4];
int n, ac[N];
void build(int left, int right, int i)
{
as[i].left = left;
as[i].right = right;
int mid = (left + right)/2;
if(left == right)
{
as[i].val = ac[left];
return ;
}
build(left, mid, 2*i);
build(mid+1, right, 2*i+1);
as[i].val = max(as[i*2].val, as[2*i+1].val);
}
void query(int left, int right, int i, int &ans)
{
if(as[i].left == left && as[i].right == right)
{
ans = max(as[i].val, ans);
return ;
}
int mid = (as[i].left + as[i].right)/2;
if(right <= mid) query(left, right, 2*i, ans);
else if(left > mid) query(left, right, 2*i+1, ans);
else
{
query(left, mid, 2*i, ans);
query(mid+1, right, 2*i+1, ans);
}
}
int main()
{
int T, Q;
scanf("%d", &T);
while(T--)
{
scanf("%d", &n);
for(int i = 1; i <= n; i++)
scanf("%d", &ac[i]);
build(1, n, 1);
scanf("%d", &Q);
while(Q--)
{
int a, b;
scanf("%d %d", &a, &b);
int ans = 0;
query(a, b, 1, ans);
printf("%d\n", ans);
}
}
return 0;
}
原文:http://www.cnblogs.com/PersistFaith/p/4808128.html