http://acm.hdu.edu.cn/showproblem.php?pid=2846
When you go shopping, you can search in repository for avalible merchandises by the computers and internet. First you give the search system a name about something, then the system responds with the results. Now you are given a lot merchandise names in repository and some queries, and required to simulate the process.
There is only one case. First there is an integer P (1<=P<=10000)representing the number of the merchanidse names in the repository. The next P lines each contain a string (it‘s length isn‘t beyond 20,and all the letters are lowercase).Then there is an integer Q(1<=Q<=100000) representing the number of the queries. The next Q lines each contains a string(the same limitation as foregoing descriptions) as the searching condition.
For each query, you just output the number of the merchandises, whose names contain the search string as their substrings.
20
ad
ae
af
ag
ah
ai
aj
ak
al
ads
add
ade
adf
adg
adh
adi
adj
adk
adl
aes
5
b
a
d
ad
s
0
20
11
11
2
字典树，g++ mle c++ ac。。
#include<algorithm>
#include<iostream>
#include<cstdlib>
#include<cstring>
#include<cstdio>
#include<vector>
#include<set>
using std::set;
using std::min;
using std::find;
using std::pair;
using std::vector;
using std::multiset;
#define pb(e) push_back(e)
#define sz(c) (int)(c).size()
#define mp(a, b) make_pair(a, b)
#define all(c) (c).begin(), (c).end()
#define iter(c) __typeof((c).begin())
#define cls(arr, val) memset(arr, val, sizeof(arr))
#define cpresent(c, e) (find(all(c), (e)) != (c).end())
#define rep(i, n) for(int i = 0; i < (int)n; i++)
#define tr(c, i) for(iter(c) i = (c).begin(); i != (c).end(); ++i)
const int N = 100010;
const int INF = 0x3f3f3f3f;
struct Node {
Node *ch[26];
int cnt;
int f;
Node() {
rep(i, 26) ch[i] = NULL;
cnt = 0;
f = -1;
}
}*root;
void insert(Node *x, char *str, int f) {
int d = 0;
char *p = str;
while (*p != ‘\0‘) {
d = *p - ‘a‘;
if (!x->ch[d]) x->ch[d] = new Node();
x = x->ch[d];
if (x->f != f) {
x->f = f;
x->cnt++;
}
p++;
}
}
int query(Node *x, char *str) {
char *p = str;
while (*p != ‘\0‘) {
if (!x || !x->ch[*p - ‘a‘]) return 0;
x = x->ch[*p - ‘a‘];
p++;
}
return x->cnt;
}
void built(int t) {
int n;
char buf[100];
rep(i, t) {
scanf("%s", buf);
n = strlen(buf);
rep(j, n) {
insert(root, buf + j, i);
}
}
}
void solve(int n) {
int m;
char buf[100];
root = new Node();
built(n);
scanf("%d", &m);
while (m--) {
scanf("%s", buf);
printf("%d\n", query(root, buf));
}
}
int main() {
#ifdef LOCAL
freopen("in.txt", "r", stdin);
freopen("out.txt", "w+", stdout);
#endif
int n;
while (~scanf("%d", &n)) {
solve(n);
}
return 0;
}
原文：http://www.cnblogs.com/GadyPu/p/4792900.html