Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131070/65535 K (Java/Others)
Total Submission(s): 25579    Accepted Submission(s): 10451
题目大意:
给你很多个长度不超过10的单词,组成了一个字典,让后,给你很多个前缀,问你以这个前缀为前缀的单词总共有多少个。
解题思路:
简单的trie应用。
指针版本
代码:
# include<cstdio>
# include<iostream>
# include<algorithm>
# include<cstring>
using namespace std;
struct trie
{
    trie * nxt[26];
    int cnt;
};
trie * root = new trie;
void insert( char * str )
{
    trie * p = root;
    trie * newnode;
    for ( int i = 0;str[i];i++ )
    {
        if ( p->nxt[str[i]-‘a‘]==0 )
        {
            newnode = new trie;
            for ( int j = 0;j < 26;j++ )
            {
                newnode->nxt[j] = NULL;
            }
            newnode->cnt = 1;
            p->nxt[str[i]-‘a‘] = newnode;
            p = newnode;
        }
        else
        {
            p = p->nxt[str[i]-‘a‘];
            p->cnt++;
        }
    }
}
int find ( char * str )
{
    trie * p = root;
    for ( int i = 0;str[i];i++ )
    {
        if ( p->nxt[str[i]-‘a‘]!=NULL )
        {
            p = p->nxt[str[i]-‘a‘];
        }
        else
            return 0;
    }
    return p->cnt;
}
/*void Release(trie *p)
{
    if (p == NULL)
        return ;
    for (int i = 0;i < 26;i ++)
        if (p->nxt[i] != NULL)
            Release(p->nxt[i]);
    free(p);
    root = NULL;
    return ;
}*/
int main(void)
{
    char str[15];
    for ( int i = 0;i < 26;i++ )
    {
        root->nxt[i] = NULL;
    }
    root->cnt = 0;
    while ( gets(str) )
    {
        if ( strcmp(str,"")==0 )
            break;
        insert(str);
    }
    while ( scanf("%s",str)!=EOF )
    {
        printf("%d\n",find(str));
    }
    //Release(root);
    return 0;
}
数组版本:
# include<cstdio>
# include<cstring>
# include<iostream>
using namespace std;
const int root=0;
int tot;
struct node
{
    int cnt;
    int next[26];
    void newnode()
    {
        cnt=0;
        for(int i=0;i<26;i++)
        {
            next[i]=-1;
        }
    }
}t[1000005];
void clear()
{
    tot=0;
    t[root].newnode();
}
void insert(char *str)
{
    int p=root;
    int len=strlen(str);
    for(int i=0;i<len;i++)
    {
        int id=str[i]-‘a‘;
        if(t[p].next[id]==-1)
        {
            t[++tot].newnode();
            t[p].next[id]=tot;
        }
        p=t[p].next[id];
        t[p].cnt++;
    }
}
int find(char *str)
{
    int p=root;
    int len=strlen(str);
    for(int i=0;i<len;i++)
    {
        int id=str[i]-‘a‘;
        if(t[p].next[id]==-1)
        {
            return 0;
        }
        p=t[p].next[id];
    }
    return t[p].cnt;
}
int main(void)
{
    char str[15];
    clear();
    while( gets(str) )
    {
        if ( strcmp(str,"")==0 )
            break;
        insert(str);
    }
    while( scanf("%s",str)!=EOF )
    {
        printf("%d\n",find(str));
    }
    return 0;
}
原文:http://www.cnblogs.com/wikioibai/p/4783318.html