Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below.
For example, given the following triangle
[
[2],
[3,4],
[6,5,7],
[4,1,8,3]
]
?
The minimum path sum from top to bottom is?11?(i.e.,?2?+?3?+?5?+?1?= 11).
?
public class Solution {
public int minimumTotal(List<List<Integer>> triangle) {
if (triangle.size() == 1) {
return triangle.get(0).get(0);
}
int[] dp = new int[triangle.size()];
for (int i = 0; i < triangle.get(triangle.size()-1).size(); i++) {
dp[i] = triangle.get(triangle.size()-1).get(i);
}
for (int i = triangle.size()-2; i >= 0; i--) {
for (int j = 0; j < triangle.get(i).size(); j++) {
dp[j] = Math.min(dp[j], dp[j+1]) + triangle.get(i).get(j);
}
}
return dp[0];
}
}
?
原文:http://hcx2013.iteye.com/blog/2240622