首页 > 其他 > 详细

[LeetCode 191] Number of 1 Bits

时间:2015-09-02 18:56:38      阅读:241      评论:0      收藏:0      [点我收藏+]

Write a function that takes an unsigned integer and returns the number of ’1‘ bits it has (also known as the Hamming weight).

For example, the 32-bit integer ’11‘ has binary representation 00000000000000000000000000001011, so the function should return 3.

solution:

1. every time n&1, until n==0. 

2. n&(n-1) will remove last 1 digit in n, use this to count how many 1 in the number


public int hammingWeight(int n) {
        int count = 0;
        while(n!=0){
            n = (n-1) & n;
            count++;
        }
        return count;
    }




版权声明:本文为博主原创文章,未经博主允许不得转载。

[LeetCode 191] Number of 1 Bits

原文:http://blog.csdn.net/sbitswc/article/details/48176391

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!