题目：
Given a binary tree, return all root-to-leaf paths.
For example, given the following binary tree:
1 / 2 3 5
All root-to-leaf paths are:
["1->2->5", "1->3"]题解：
用深度优先遍历，类似二叉树的前序变遍历
代码：
public class LeetCode257_BinaryTreePaths {
static List<String> paths=new ArrayList<>();
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
TreeNode p1=new TreeNode(1);
TreeNode p2=new TreeNode(2);
// TreeNode p3=new TreeNode(3);
// TreeNode p4=new TreeNode(5);
p1.left=p2;
// p1.right=p3;
// p2.left=p4;
binaryTreePaths(p1);
}
public static List<String> binaryTreePaths(TreeNode root) {
if(root==null)
return paths;
String curPath="";
serachTree(root, curPath);
return paths;
}
public static void serachTree(TreeNode root,String currentPath) {
currentPath+=root.val;
if(root.left==null&&root.right==null)
{
paths.add(currentPath);
System.out.println(currentPath);
return;
}
currentPath+="->";
if(root.left!=null)
serachTree(root.left, currentPath);
if(root.right!=null)
serachTree(root.right, currentPath);
}
}
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LeetCode257 BinaryTreePaths(打印根节点到叶子节点的左右路径) Java题解
原文：http://blog.csdn.net/u012249528/article/details/47816499