1 2 0 1 2 0 1 1 2 2 4 0 1 2 3 4 5 0 3 0 4 1 3 1 4
yes no
#include <iostream>
#include <cstring>
#include <cstdlib>
#include <cstdio>
#include <cmath>
#include <vector>
#include <queue>
#include <algorithm>
#include <stack>
#include <set>
#include <map>
#define LL long long
using namespace std;
const int MAXN = 20010;
vector<int>G[MAXN];
int pre[MAXN], lowlink[MAXN], sccno[MAXN], dfs_clock, scc_cnt;
stack<int> s;
void dfs(int u)
{
pre[u] = lowlink[u] = ++dfs_clock;
s.push(u); int sz = G[u].size();
for(int i=0;i<sz;i++)
{
int v = G[u][i];
if(!pre[v])
{
dfs(v);
lowlink[u] = min(lowlink[u], lowlink[v]);
}
else if(!sccno[v])
{
lowlink[u] = min(lowlink[u], pre[v]);
}
}
if(lowlink[u] == pre[u])
{
scc_cnt++;
for(;;)
{
int x = s.top(); s.pop();
sccno[x] = scc_cnt;
if(x == u) break;
}
}
}
void find_scc(int n)
{
dfs_clock = scc_cnt = 0;
memset(sccno, 0, sizeof(sccno));
memset(pre, 0, sizeof(pre));
for(int i=1;i<=n;i++) if(!pre[i])
dfs(i);
}
int N, M, T;
int main()
{
while(scanf("%d%d", &T, &M)!=EOF)
{
int x, y, z;
N = 3 * T;
for(int i=0;i<=2*N;i++) G[i].clear();
for(int i=1;i<=T;i++)
{
scanf("%d%d%d", &x, &y, &z);
x++; y++; z++;
G[x+N].push_back(y);
G[x+N].push_back(z);
G[y+N].push_back(x);
G[z+N].push_back(x);
}
for(int i=1;i<=M;i++)
{
scanf("%d%d", &x, &y);
x++; y++;
G[x].push_back(y + N);
G[y].push_back(x + N);
}
find_scc(2 * N);
int flag = 1;
for(int i=1;i<=N;i++)
{
if(sccno[i] == sccno[i + N])
{
flag = 0;
break;
}
}
if(flag) puts("yes");
else puts("no");
}
return 0;
}版权声明:本文为博主原创文章,未经博主允许不得转载。
HDU 1824 Let's go home (2-SAT判定)
原文:http://blog.csdn.net/moguxiaozhe/article/details/47782479