Time Limit: 1000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 3273    Accepted Submission(s): 
1320
#include<stdio.h>
#include<string.h>
#define INF 0x3f3f3f
#define min(x,y)(x<y?x:y)
#define MAX 1010
int n,m;
int map[MAX][MAX];
int dis[MAX][MAX];
void init()
{
	int i,j;
	for(i=1;i<=n;i++)
	    for(j=1;j<=n;j++)
		{
	    	map[i][j]=i==j?0:INF;
    	    dis[i][j]=i==j?0:INF;
		}     
}
void getmap()
{
	int i,j;
	for(i=1;i<=m;i++)
	{
		int a,b,c;
		scanf("%d%d%d",&a,&b,&c);
		if(map[a][b]>c)
		    map[a][b]=map[b][a]=dis[a][b]=dis[b][a]=c;
	}
}
void floyd()
{
	int i,j,k;
	int sum=INF;
	for(k=1;k<=n;k++)
	{
		for(i=1;i<k;i++)  //求最小环 
		    for(j=1;j<i;j++)
		        sum=min(sum,map[i][k]+map[k][j]+dis[j][i]);
		
		for(i=1;i<=n;i++)//更新最短路径 
			for(j=1;j<=n;j++)
			    dis[i][j]=min(dis[i][j],dis[i][k]+dis[k][j]);
	}
	if(sum==INF)
	    printf("It‘s impossible.\n");
	else 
	    printf("%d\n",sum);
}
int main()
{
	while(scanf("%d%d",&n,&m)!=EOF)
	{
		init();
		getmap();
		floyd();
	}
	return 0;
}
hdoj 1599 find the mincost route【floyd+最小环】
原文:http://www.cnblogs.com/tonghao/p/4728324.html