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hdu 5194 DZY Loves Balls

时间:2015-08-13 21:54:43      阅读:198      评论:0      收藏:0      [点我收藏+]
Problem Description
There are n black balls and m white balls in the big box.
Now, DZY starts to randomly pick out the balls one by one. It forms a sequence S. If at the i-th operation, DZY takes out the black ball, Si=1, otherwise Si=0.
DZY wants to know the expected times that ‘01‘ occurs in S.
 

 

Input
The input consists several test cases. (TestCase150)
The first line contains two integers, n, m(1n,m12)
 

 

Output
For each case, output the corresponding result, the format is p/q(p and q are coprime)
 

 

Sample Input
1 1 2 3
 

 

Sample Output
1/2 6/5

 

 1 #include<cstdio>
 2 #include<cstring>
 3 #include<algorithm>
 4 using namespace std;
 5 int m,n;
 6 void build(int x,int y,int t1,int t2,int &ans1,int &ans2)
 7 {
 8     int a,b;
 9     if (t2==m) {ans1=1;ans2=1;return ;}
10     if (t1==n)
11     {
12         if (x==0) ans2=1;
13         else ans2=0;
14         ans1=1;
15         return ;
16     }
17     build(y,0,t1,t2+1,ans1,ans2);
18     a=ans1;
19     b=ans2;
20     build(y,1,t1+1,t2,ans1,ans2);
21     a+=ans1;
22     b+=ans2;
23     if (x==0&&y==1) b+=a;
24     ans1=a;
25     ans2=b;
26 }
27 int main()
28 {
29     int a,b,c,ans1,ans2;
30     while (~scanf("%d%d",&n,&m))
31     {
32         build(-1,0,0,1,ans1,ans2);
33         a=ans1;b=ans2;
34         build(-1,1,1,0,ans1,ans2);
35         a+=ans1;b+=ans2;
36         n=b;
37         m=a;
38         a=max(n,m);
39         b=min(n,m);
40         c=1;
41         while (c)
42         {
43             c=a%b;
44             a=b;
45             b=c;
46         }
47         printf("%d/%d\n",n/a,m/a);
48     }
49     return 0;
50 }

 

hdu 5194 DZY Loves Balls

原文:http://www.cnblogs.com/pblr/p/4728291.html

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