首页 > 其他 > 详细

[leedcode 198] House Robber

时间:2015-08-03 22:21:21      阅读:224      评论:0      收藏:0      [点我收藏+]

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will automatically contact the police if two adjacent houses were broken into on the same night.

Given a list of non-negative integers representing the amount of money of each house, determine the maximum amount of money you can rob tonight without alerting the police.

public class Solution {
    public int rob(int[] nums) {
        //注意中间变量的含义:unrob表示当前房子没有被偷。rob表示当前房子被偷了
        int robbed=0;
        int unrobbed=0;
        int res=0;
        for(int i=0;i<nums.length;i++){
            int temp=unrobbed;
            unrobbed=Math.max(unrobbed,robbed);
            robbed=nums[i]+temp;
            
        }
        return Math.max(unrobbed,robbed);
    }
}

 

[leedcode 198] House Robber

原文:http://www.cnblogs.com/qiaomu/p/4700341.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!