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HDU 5224 Tom and paper(最小周长)

时间:2015-08-01 15:27:26      阅读:104      评论:0      收藏:0      [点我收藏+]

 

HDU 5224 Tom and paper(最小周长)

 

Time Limit:1000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u
 

Description

There is a piece of paper in front of Tom, its length and width are integer. Tom knows the area of this paper, he wants to know the minimum perimeter of this paper.
 

Input

In the first line, there is an integer T indicates the number of test cases. In the next T lines, there is only one integer n in every line, indicates the area of paper. 
T<=10,n<= 10^9
 

Output

For each case, output a integer, indicates the answer.
 

Sample Input

3 2 7 12
 

Sample Output

6 16 14
 
 
 
题解:给出面积求最小周长问题,数学问题
 
AC代码
#include<cstdio>
#include<cmath>
int main()
{
    int t,s,n;
    scanf("%d",&t);
    while(t--)
    {
        scanf("%d",&s);
        n=(int)sqrt((double) s);
        while(s%n)
            n--;
        n=2*(n+s/n);
    printf("%d\n",n);
    }
return 0;
}

 

 

HDU 5224 Tom and paper(最小周长)

原文:http://www.cnblogs.com/hfc-xx/p/4694098.html

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